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5^x+(1/5)^2x-3=0
Domain of the equation: 5)^2x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5^x+(+1/5)^2x-3=0
We multiply all the terms by the denominator
5^x*5)^2x+(-3*5)^2x+1=0
We add all the numbers together, and all the variables
5^x*5)^2x+(-15)^2x+1=0
Wy multiply elements
25x^2-15)^2x+1=0
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